#### syamin0712

##### Member level 1

What I understand about I to V converter using op Amp is that the output voltage will equal to the resistor x current input that we have.

Something like this figure:

https://obrazki.elektroda.pl/1069454400_1442453480.png

So that the output voltage will be

Vout = -IsxRL

However,

when I simulated the circuit; in my case the current input is 2.5mA with operating frequency is 2MHz, and I'm using LT6200CS8-5 as my op amp.

https://obrazki.elektroda.pl/3328319100_1442453788.png

Noticed that, the 1k ohm resistor and 4.7pF capacitor are to stabilize the circuit only.So that, the current value is maintain.

If using the above equation; Vout= -2.5mA x 1.2kohm =-3 Vp-p

The output value was not same as the equation above. The Vp-p is around 8.64 Vp-p.

Could anybody explain it to me what is the error and how to solve it.

Or that equation will get the output in RMS value?

Thank you in advanced.