pixel
Advanced Member level 2
This is one practical measurement problem. I have resistor divider Rs, Rp and capacitance Cp in parallel with Rp, connected to gnd.
Here are circuit equations:
Iin = Vin*(1+s*Cp*Rp)/(Rp+Rs+s*Cp*Rs*Rp)
Iin = Vin*(Rp+Rs+Rs(wCpRp)^2+jw*Cp*Rp*Rp)/((Rp+Rs)^2+(w*Cp*Rs*Rp)^2)
v[Cp]=v[Rp]=(Rp*Vin)/(Rp+Rs+s*Cp*Rs*Rp)
i[Rp] = v[Cp]/Rp
i[Cp]=v[Cp]*s*Cp
Input admitance: Y=Iin/Vin=A(w)+jB(w)
I can measure only admitance vector Y (or Iin), i.e. A(w) and B(w) values at frequenciues w1 and w2. How can be Rp, Rs and Cp identiified ?
Here are circuit equations:
Iin = Vin*(1+s*Cp*Rp)/(Rp+Rs+s*Cp*Rs*Rp)
Iin = Vin*(Rp+Rs+Rs(wCpRp)^2+jw*Cp*Rp*Rp)/((Rp+Rs)^2+(w*Cp*Rs*Rp)^2)
v[Cp]=v[Rp]=(Rp*Vin)/(Rp+Rs+s*Cp*Rs*Rp)
i[Rp] = v[Cp]/Rp
i[Cp]=v[Cp]*s*Cp
Input admitance: Y=Iin/Vin=A(w)+jB(w)
I can measure only admitance vector Y (or Iin), i.e. A(w) and B(w) values at frequenciues w1 and w2. How can be Rp, Rs and Cp identiified ?