Jun 7, 2010 #1 A amad_nugent Newbie level 2 Joined Jun 7, 2010 Messages 2 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,290 Can someone explain why the ratio of junction area of the output devices to the biasing diodes come into play? why its important? thanks a lot
Can someone explain why the ratio of junction area of the output devices to the biasing diodes come into play? why its important? thanks a lot
Jun 7, 2010 #2 flatulent Advanced Member level 6 Joined Jul 19, 2002 Messages 4,624 Helped 489 Reputation 980 Reaction score 151 Trophy points 1,343 Location Middle Earth Activity points 46,689 Since the diode is in parallel with the base emitter, they have the same voltage across them. Higher cross sectional area for a given voltage produces higher current.
Since the diode is in parallel with the base emitter, they have the same voltage across them. Higher cross sectional area for a given voltage produces higher current.
Jun 7, 2010 #3 A amad_nugent Newbie level 2 Joined Jun 7, 2010 Messages 2 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,290 why does Quiescent current= n*Ibias? n is the ratio of the diode size to the transistor size