Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Class A amplifier operation

Status
Not open for further replies.

muheeb16

Member level 3
Member level 3
Joined
Jul 18, 2015
Messages
55
Helped
1
Reputation
2
Reaction score
1
Trophy points
8
Activity points
416
I know for transformer coupled circuits when current becomes zero the back emf acts and the collector to emitter voltage is increased.But why does it becomes exactly 2Vcc.I am actually having trouble figuring out the value of back emf offered amp22.gif
 

But why does it becomes exactly 2Vcc.
Some presumptions.
1. Symmetrical input signal, e.g. a sine
2. linear amplifier, linear load (speaker)
3. Sufficient large transformer inductance (ideally infinite)
4. Transistor bias current >= Vcc/(N²*RL)

There's no sense in making the positive voltage swing higher than the negative swing. The negative swing is however smaller than Vcc by the RE voltage drop and transistor saturation voltage.
 

Transistorized audio amplifiers have not used an output transformer for about 60 years.
By far, most audio amplifiers are class-AB, not class-A.
 

It is not from the back EMF but rather since the Collector DC voltage, Vc =Vcc from ANY COIL with low DCR. It doesn't have to be a transformer, but the impedance on the collect to emitter ratio determines Voltage gain.

The coil can store energy and swing voltage symmetrically around Vcc thus the maximum Vce , Vpp=2Vcc ( minus Ve)
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top