Re: Can any one help me with these equtions?
About the first question, the derivation of (7) and (8) from (6) is very simple; we have:
R=B*n*log2(1+g/gef) then
R/(B*n)=log2(1+g/gef)
by definition the logarithm is the exponent to which the base must be raised to have the number. That is "logb(N)=a" means "b^a=N" so, in our case the base is 2, the exponent R/(B*n) and the number 1+g/gef:
2^[R/(B*n)]=1+g/gef thus
2^[R/(B*n)]-1=g/gef then
ge=gef*{2^[R/(B*n)]-1}
About the second question, (13), (14) and (15) are not derived by (12) but from what's written in section III-B