A bandpass signal has lower frequency 1002.5 khz and higher frequency 1046 khz. Determine the minimum sampling rate so as to have a minimum guard band of 4khz between two spectrum replicas.
Could you clarify this, FvM? From what you're saying, I guess we're not talking about complex baseband signals (which is what I'm familiar with). Was there something in the wording of the original question that made this clear?
Is it clear from the original question that this is the case? I'm worried that I've worked too much with complex baseband representation and can't recognise a real signal when I see it...
Is it clear from the original question that this is the case? I'm worried that I've worked too much with complex baseband representation and can't recognise a real signal when I see it...
It's not explicitely stated. But obviously the question is just an excercise problem about sampling. Complex signals and quadrature demodulation are advanced stuff beyond basic sampling theory.
I didn't even realize this background of your first post, I suspected a simple calculation error...
According to me, the frequenc must be (1046 + 2)*2 = 2096Khz.
For details, conside the diagram below...
Here as we can see B represents our upper limit, ie., 1046kHz. now if on one side, we add a ban of 2kHz, we will get this 2k and another 2k from the periodic signal.. thus eventually a 4k guard band. Thus the sampling frequency must be 2*(1046 + 2)