C programming, problem assigning string

Hi everyone,

I have the following problem doing string assignment with C18 microchip compiler.

For example, I am able to assign this way

const rom unsigned char testing[]={"GMxxx"};

what appear in memory is G,M,x,x,x


When I do it in another way, the data in memory becomes

const rom unsigned char testing[]={"GMxxx",0x00};

what appear in memory is 0x0E, ...

I hope if someone can explain to me what's going on???


I hope to append 0x0D 0x0A to the end of the string...
Is there any way I can do it in C18 compiler.
I am thinking of doing the following but the data retrieved is not what I want.

const rom unsigned char testing[]={"GMxxx",0x0D,0x0A};


Any alternative?

Thank you so much.
Siong Boon

just try :

const rom unsigned char testing[]={"GMxxx\r\n"};

Hi aProgrammer,

It works. Thank you very much.

Best Regards,
Siong Boon

I don't see how char testing[] = ("Gmxx", 0xa, 0xd); would even compile. It won't on my compiler. You are giving it a 5 byte value with "Gmxx" when it expects a single byte. You can't mix up strings of chars with individual chars.


char testing[]={'G','m','x','x', 0xd, 0xa, '0'}; should also work

Thanks jhbbunch,

this is also the solution I am looking for, for non ascii char.
Thank you.

Thanks for the reply. I should note that I made a mistake in the code. The last value should be 0, not '0' (ascii 0). 0 of course is the string terminating character in C. ASCII 0 is a printable character.

For using strings please burn your data in in ROM than use strings in C programming