C problem.. urgent need of help

[dck]

how can i store strings into an array and display it???

here is the half-way program.. i got stucked..
thnx...

#include<stdio.h>
main()
{
char name[50];
int i;

for(i=0;i<5;i++)
{
printf("Please enter name:");
gets(name);
}

for(i=0;i<5;i++)
printf("%s\n", name);
}

 

[btbass]

Here is a version but it lacks error checking.

#include<stdio.h>
#include<stdlib.h>
#include <string.h>

int main(void)
{
char buffer[50];
char *name[5];
int i; 

for(i = 0; i < 5; i++)
  {
  printf("Please enter name:");
  gets(buffer);
  name[i] = malloc(strlen(buffer));
  strcpy(name[i], buffer);
  }

for(i = 0; i < 5; i++){
  printf("%s\n", name[i]);
  }

return 0;
}

 

[dck]

can u jus do it only using stdio.h lib??
coz im only most familiar wit that lib..
=)

 

[btbass]

They are all part of the standard c library, they will exsist in your compiler.
If you are going to use strings, it is worthwhile looking at the functions in <string.h>

You could do it using a 2 dimension array,
name[5][50];
But this will waste a lot of memory.

 

[ahmon_abilar]

#include<stdio.h>
main()
{
char name[50];
int i;

printf("Please enter name:");
scanf("%s", &name);

printf("%s", name);
}

Added after 2 minutes:

#include<stdio.h>
main()
{
char name[5][50];
int i;

for(i=0; i<5; ++i)
{
printf("Please enter name:");
scanf("%s", &name);
}

for(i=0; i<5; ++i)
{
printf("%s", name);
}
}