Boolean Algebra

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sxy

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Hi
Why the folllowing equation is correct:
L'C+I'C+L'I=L'C+L'I
thanks
 

Did you try put these terms into the K-map ?
There you can find out what terms can be simplified.
 

Hi
Why the folllowing equation is correct:
L'C+I'C+L'I=L'C+L'I
thanks
Using consensus theorem (XY + X'Z + YZ = XY + X'Z)
let L' = X
let C = Y
let I = Z

Hence your expression becomes:
XY + Z'Y + XZ
rearrange as XZ + YZ' + XY

Hence based on above theory XY is redundant:
= XZ + YZ'
i.e. = I'C + L'I

So either I or you may have typing error.
 

Hi
If you do the truth table for every side of the equation;
you will see that they are equal to each other; but I didn't succed to prove in in the terms of Boolean Algebra.
thank you very much for your answer.
 

As already said by std_match in post #2 the equation can't be correct. If you need an example simply let: I=0, C=1 and L=1 then LHS we have

0*1 + 1*1 + 0*0 = 1

RHS, intstead

0*1 + 0*0 = 0

Thus RHS <> LHS

Possibly your equation contains a typo, please check it.
 
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