naresh850
Full Member level 3
Hi,
In Bilinear transformation s-plane is transformed in z- plane by formulla.
s = (2/T)(1-z^-1)/(1+z^-1); T = Sampling time period
in analog domain
s = d/dt
its in discrete domain
dx/dt = (x-x(n-1))/T where is x(t) is analog signal.T = Sampling time period
so s = (1-z^-1)/T
But in bilinear transform, why 2/(1+z^-1) is added in to define s?
Reagards,
NP
In Bilinear transformation s-plane is transformed in z- plane by formulla.
s = (2/T)(1-z^-1)/(1+z^-1); T = Sampling time period
in analog domain
s = d/dt
its in discrete domain
dx/dt = (x-x(n-1))/T where is x(t) is analog signal.T = Sampling time period
so s = (1-z^-1)/T
But in bilinear transform, why 2/(1+z^-1) is added in to define s?
Reagards,
NP