i want to use a MOSFET as a bidirectional switch for circuit breaker applications. now the problem that i have is the body diode of the device. is there a way whereby i can bypass this diode (as if the MOSFET doesn't have it)?.
This may be solved by two N-MOSFET in series and their drains connected.
The difficulty of this method is that one of the N-MOSFET (or both) should be driven by a floating driver.
This may be solved by two N-MOSFET in series and their drains connected.
The difficulty of this method is that one of the N-MOSFET (or both) should be driven by a floating driver.
"Same voltage" means Vgs or Vds? By the connection shown in your schematic in post #7, both MOSFETs get the same Vgs, as required. Vds is of course different.
You don't need any diodes. But MOSFET substrate diodes are present.
"Same voltage" means Vgs or Vds? By the connection shown in your schematic in post #7, both MOSFETs get the same Vgs, as required. Vds is of course different.
You don't need any diodes. But MOSFET substrate diodes are present.