stanford
Full Member level 2
Non-blocking assignment evaluates the RHS expression at the beginning of a time step and schedules the LHS update to take
place at the end of the time step.
Let's say we have
If we have a non-blocking assignment inside a always_ff block, does the beginning of a timestep mean the current clock edge and the end of the time step mean the next clk edge? So that (a | b) is evaluated in the current clock edge but the assignment happens in the next clk edge?
Thanks!
place at the end of the time step.
Let's say we have
Code:
always_ff @(posedge clk)
c <= a | b;
Thanks!