A dummy question!
When we analyse circuits containing ideal transformers, we describe the transformer by the equation below:
v2/v1=n, where n is the ratio between the number of turns in secondary to the number of turns in primary.
But, what if i place a voltage source in primary and short circuit the secondary?
if its a "perfect "transformer, then it will reflect a short circuit back, so the current will be infinite. In real life the transformer will have a DC resistance in both windings and leakage inductance, this appears as a small series inductance to the reflected impedance and the series DC resistance. This will then reduce the current from infinite to an actual (high) figure.
Frank