#### User4

##### Newbie level 4

I have a circuit containing a capacitor and probably also a resistor, but I am not sure of the configuration.

I have tried to measure the capacitance by passing a triangular waveform potential through the circuit. If it were just a capacitor I would expect to get a square waveform out. However I see the following: -

**broken link removed**

*The inputs in the graphs are potential vs time, the outputs are current vs time.

I think this may be due to a resistor in the circuit.

If it were a simple square waveform output I would simply calculate the capacitance to be C=i/(dV/dt), where the value of 'i' would be the amplitude of the square wave.

So I have the following questions: -

- which points on the graph should I be using to measure 'i'?
- what is the cause of the slope?
- If this is caused by a resistance, would it be in series or in parallel?
- what other information can I get from this graph? - i.e. does the gradient of the slope allow calculation of the resistance of the resistor?

Thank you for any help you can give me.