Nov 8, 2004 #21 M movingbait Member level 2 Joined Apr 23, 2004 Messages 48 Helped 4 Reputation 8 Reaction score 0 Trophy points 1,286 Activity points 444 who dont you 1st design it with op-amps and than make a simple opamp on the transistor/fet level like a 741, there are schematics for it everywhere.
who dont you 1st design it with op-amps and than make a simple opamp on the transistor/fet level like a 741, there are schematics for it everywhere.
Nov 9, 2004 #22 N nand_gates Advanced Member level 3 Joined Jul 19, 2004 Messages 899 Helped 175 Reputation 350 Reaction score 53 Trophy points 1,308 Activity points 7,037 Hi Friends, Can't we use NORTAN opamp for this?? -nand_gates
Nov 18, 2004 #23 T tufan Junior Member level 3 Joined Oct 3, 2004 Messages 26 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 228 Hey..Thanks every body... What 's a nortan op-amp?please tell me..
Nov 20, 2004 #24 F fashion Junior Member level 3 Joined Sep 1, 2004 Messages 29 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 176 I think what you want is ECL-like structure to implement it, it can get high noise rejection and high speed, but power consuption is large
I think what you want is ECL-like structure to implement it, it can get high noise rejection and high speed, but power consuption is large
May 16, 2006 #25 M Manoochehr Junior Member level 3 Joined Oct 11, 2001 Messages 27 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 160 I think that if both of (I1+I2) and (I1-I2) are positive, you can use "log" and "exp" functions (using OpAmps) to devide those currents. I mean : exp( log(I1-I2)-log(I1+I2))=(I1-I2)/(I1+I2) You have to investigate the required accuracy.
I think that if both of (I1+I2) and (I1-I2) are positive, you can use "log" and "exp" functions (using OpAmps) to devide those currents. I mean : exp( log(I1-I2)-log(I1+I2))=(I1-I2)/(I1+I2) You have to investigate the required accuracy.
Nov 14, 2006 #26 W wonbef Full Member level 3 Joined Oct 13, 2004 Messages 188 Helped 8 Reputation 16 Reaction score 6 Trophy points 1,298 Location Nanshan, Shenzhen Activity points 1,083 i think the current solution is a good selection. good luck