He said the output current is AC, so I guess the output voltage will be AC as well, unless there's an extremely unusual load.
Since the OP's not exactly forthcoming with detailed requirements, the smart option would probably be to design a power amp running off a supply of +-10V or so, capable of 5A rms output current and 5V rms output voltage, with a current-sense resistor for the feedback. I'm not sufficiently bored to tackle that right now though.
Actually, I get the distinct impression the OP doesn't really know what the requirements are, and is just guessing at the output voltage.
Frequency is 50Hz,
Sine waveshape
+12Vdc power source or +24V dc power source
I have a energy meter of input (0-5) Amps and also I have CT giving the output of (0-333) mV so i want to connect the CT to my energy meter. For that I want to convert the AC voltage of (0-333)mV to AC current (0-5)Amps. This is exact purpose of my project.
The question is, if the current you are measuring is 5A and the energy meter measures 5A, why do you need an interface circuit? Is the current transformer required for isolation?
What is the turns ratio of the transformer?
You could just use an identical current transformer, connected in reverse to the first transformer, to convert the output current of the first transformer back to 5A.