I hope not "directely" but via 7805.i powered my 89s52 directly to the 7.4v battery
Yes.... my microcontroller input voltage is betwwen 4.5 to 5v.Hi,
can you confirm that your microcontroller current is within the specified (datasheet) range?
If so, then you need to use power down features.
How to decrease current consumption:
* switch off all unnecessary external circuit
* use power down features
* use low frequency clock
* use internal RC clock (if possible)
* all I/O should be very near VCC or GND (no floating, no value inbetween)
* use low supply voltage
* use low power microcontroller
Klaus
An interrupt (for the key press) will wake up the CPU or you can leave it in Idle mode and let a timer wake it up. Some details in the rest of the document mention the interrupt out of power-down requires the interrupt input stay active until the clock stabilizes.The Idle Mode stops the CPU while allowing the RAM, timer/counters, serial port, and
interrupt system to continue functioning. The Power-down mode saves the RAM contents
but freezes the oscillator, disabling all other chip functions until the next interrupt
or hardware reset.
It is better to use switcher than linear regulator(7805) for battery powered units.
AFAIK LDO means low dropout. But you are correct, it is a linear regulator. And every linear regulator dissipates a lot of power.7805 is a LDO. that means it dissipates some power in heat
How do you know?my 89s52 is in idle mode....
How do you know?all ports has been low...
At least show your code..., a picture of your circuit where we can see the voltage and current measurement.what should i do now..
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