You will find very few regulators that have lower drop than 1V; the regulator needs some space to work. Perhaps you can get one with a 0.9V dropout but then they are rare.
Anyway you will that 4V input cannot reliably produce 3.3V regulated output (most cases)
So your input voltage is not exactly 5.0V.
Rather expect 4.2V ..... 5.5V (it is specified down to 4.5V, but I've seen many they go below this at the end of the cable)
i don't have oscilloscope, can you say that i should go with mentioned value of capacitor (as datasheet)?
you must not rely on any MCU manufacturer recommendation when you want stable XC6206 operation.
Rely on the XC6206 datasheet.
it clearely says to use 1uF ceramics each at input and output.
Additionally it says: ...
3. Please wire the input capacitor (C IN ) and the output capacitor (C L ) as close to the IC as possible.
4. Capacitances of these capacitors (C IN , C L ) are decreased by the influences of bias voltage and ambient temperature. Care
shall be taken for capacitor selection to ensure stability of phase compensation from the point of ESR influence.
for stable MCU operation you need to follow the recommendations in the MCU datasheet.
If they recommend to use 10nF capacitors then do so.
But read carefully. Usually they recommend one capacitor very close at each VCC pin of the IC....this has nothing to do with the capacitors close to the voltage regulator.
Datasheet of XC6206 informs that output voltage can be selected(6th line, 1st page of datasheet). But how? There is no additional pin for select output. https://www.torexsemi.com/file/xc6206/XC6206.pdf
You will find very few regulators that have lower drop than 1V; the regulator needs some space to work. Perhaps you can get one with a 0.9V dropout but then they are rare.
Anyway you will that 4V input cannot reliably produce 3.3V regulated output (most cases)
You can find MANY regulators with less than 1V of dropout. But what is it you really want? You say you want 5V to 3.3V, that 1.7V of acceptable dropout