Some numbers don't fit. Not considering losses, you get an average input current of 420W/12V=35A. The inductor has to be designed for this current. A 7 Ah battery won't be well suited to deliver 35A (or 40-45 A, considering realistic losses).
Apart from this point, a boost converter isn't a good choice for a 1:35 voltage ratio due to high switching losses. A push-pull transformer converter would be a more reasonable option.
Some numbers don't fit. Not considering losses, you get an average input current of 420W/12V=35A. The inductor has to be designed for this current. A 7 Ah battery won't be well suited to deliver 35A (or 40-45 A, considering realistic losses).
Apart from this point, a boost converter isn't a good choice for a 1:35 voltage ratio due to high switching losses. A push-pull transformer converter would be a more reasonable option.
Depends on flash rate you want the strobe to work at. You can stepup the voltage and discharge from a LOW ESR plastic cap easily with very low current and wait or higher current for faster recharge cycle time. But the power in the Xenon tube is determined by 1/2 CV^2 and the Energy power-time constant in Watt-Seconds is the figure of brightness ( or Joules) . The ESR of the tube and its energy rating in W-sec determine the peak brightness and duration of the pulse.
To simulate the sun, you need 1 kW-Sec or 1 KJ reflected over 1 sq m. (m^2)