Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

[SOLVED] 4 bits serial in/parel out register in verilog

Status
Not open for further replies.

nick_20

Newbie level 3
Joined
Mar 27, 2011
Messages
3
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,297
hey!! can someone provide me with the behavioral description code of a 4-bit shift register with a serial input and and parel output in verilog
i am looking for something like this**broken link removed**
 

hi

parameter shift = <shift_length>;
reg [shift-1:0] <reg_name>;
always @(posedge <clock>)
<reg_name> <= {<input>, <reg_name>[shift-1:1]};
assign <output> = <reg_name>;
 
hi

parameter shift = <shift_length>;
reg [shift-1:0] <reg_name>;
always @(posedge <clock>)
<reg_name> <= {<input>, <reg_name>[shift-1:1]};
assign <output> = <reg_name>;



can you elaborate a bit more cause i am dummy????:lol:
 
Last edited:

another example better:

module shift_register (Clk, Clear, SerialIn, ParallelOut);
input Clk, SerialIn, Clear;
output [3:0] ParallelOut;
reg [3:0] tmp; <-- your four flip-flops

always @(posedge Clk)
begin
if (Clear)
tmp <= 4'b0000;
else
tmp <= {tmp[2:0], SI}; <-- concatenation , 1 cycle : you have 1101, 2 cycle : 101+serial in data 2 cycle, 3 cycle : 01+serial in data 2 cycle + serial in data 3 cycle and so on.
end

assign ParallelOut = tmp;

endmodule
 
Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top