Junior Member level 3
In the book Analog Design Essentials, the author says that "This SR appears at the output as the VGS6 is still about constant. Indeed, transistor M6 still conducts as if nothing has happened!" But,why? Since M4 is on, the voltage of Node 1 will ultimately become low, so M6 would turn off and make Vout a high voltage. How can M6 still conduct?