Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

1st order Filter with 2 second Time Constant

Status
Not open for further replies.

digi001

Full Member level 5
Full Member level 5
Joined
Apr 5, 2011
Messages
244
Helped
22
Reputation
44
Reaction score
21
Trophy points
1,298
Visit site
Activity points
2,904
How do I design a 1st order filter with 2 second time constant?

1 / (s + ?)


Once i have it in continuous form I can convert using BiLinear and design the digital filter I need.
 

first order means an RC filter.....so RC product should be 2 seconds.
Put Z(r) = 1000 + j0
Put Z(c) = 0 + j. xc

where xc = 1/2.pi.f.C
Where C = 0.002 Farad

Now you can work it through and get vin/vout in complex numbers, ie the s parameter relation
 

I think i found now what I needed. Treez, i dont have any actual R's or C's so the problem is much simpler than that.

The form for 1st order Low Pass transfer function is:
1
----------
(1+s/wc)

with wc being the 'cutoff frequency' in radians per second

wc is the inverse of the time constant.

So actually it is very simple and my transfer function is just:
1
----------
(1+2s)


Converting to bilinear, i will let matlab handle it and give me coefficients :)

Thanks.
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top