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[SOLVED] Difference in sound between these two circuits

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carl5

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Hi,

How will be the frequency response?




123.png

Thanks
 

Hi,

to calculate cutoff frequency (fc) you need to know load resistance.

The formula for first order LPF fc is easy to find.

Klaus
 

It looks like you have a jack for headphones. Many headphones are 32 ohms for each earphone. Then 1uF cuts 5kHz and below. 10uF cuts 500Hz and below. 100uF will cut 50Hz and below. 250uF will cut very low 20Hz and below. If the load resistance is higher than 32 ohms then the cutoff frequencies will be less. Less capacitance is needed for the same cutoff frequencies as listed above.
 
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    carl5

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Hi,

When we use headphone, it has coil. while amplifier has input resistance in range of 10k. Will there any oscillations in 32ohm RLC circuit?


Thanks.
 
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Frequency response? AM has constant wave carriers and different audio signals. Cannot see clearly. Low sound or low volume. Inductive and conductive reactance is zero or cancels each other out. Forward bias. At that point where resistance is zero in circuit. Exact signal impulse, and able to hear AM radio. Constant function, flat line. I suppose. I couldn't make out the graph clearly. Making a guess what's happening.
 

When we use headphone, it has coil. while amplifier has input resistance in range of 10k. Will there any oscillations in 32ohm RLC circuit?
The reactance of the coil in an earphone barely affects audio frequencies. The earphone has a 32 ohm resistance.

I do not know why your schematic has headphones connected to other headphones with coupling capacitors. Usually headphones are connected to the output of an amplifier with a series resistor to reduce the level.
Maybe you are using the coupling capacitors to reduce the levels of only low frequencies to the headphones but the high audio frequencies are passed by the capacitors without loss to the headphones?
 

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