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14th February 2018, 11:25 #1
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equivalent circuit of tranformer referred to secondary?
Hello Everyone,
I would like to understand why when we do the equivalent circuit of transfer referred to scondary we multiply the imedance of the primary by N°2. the voltage mltiplied by N , current divided b N and vice versa when referred to the primary?
best regardsLast edited by tarikelec; 14th February 2018 at 11:34.

14th February 2018, 11:25

14th February 2018, 11:38 #2
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Re: equivalent circuit of tranformer referred to secondary?
to make the analysis/calculation simpler.

14th February 2018, 11:38

14th February 2018, 12:09 #3
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14th February 2018, 12:09

14th February 2018, 12:14 #4
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Re: equivalent circuit of tranformer referred to secondary?
Hi,
What else do you expect?
What exactly is the problem?
KlausPlease don´t contact me via PM, because there is no time to respond to them. Thank you.

14th February 2018, 13:56 #5
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Re: equivalent circuit of tranformer referred to secondary?
I want to know how did the equations and the formulas are derived from the transformer to its equivalent circuit step by step because when I look at it in teh litereture I don#t understand how did they come to the result

14th February 2018, 13:56

14th February 2018, 18:57 #6
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Re: equivalent circuit of tranformer referred to secondary?
The formulas are derived from laws governing physical phenomena (Faraday, in this case) and also from premises (the magnetic flow passing through the secondary arm is ideally equal to the one of the primary). The rest is purely mathematical development, but this is well documented on the Web in greater or lesser depth of details. Anyway, as stated above, it is a matter of simplification; if we are analyzing a particular part of a circuit, we have to reduce the remainder that is not the focus of attention to a simpler model. The classic example is when we simulate the load at the output of this transformer only by a resistor, although it is effectively a complex circuit.

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