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Current mirror layout with odd multiplier

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sthota04

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Please have a look at the current mirror below.

I Call the diode connected transistor as A and the transistor in which the current is being mirrored as B.

Capture.PNG

If A (m=1) and B (m=3), How should I place the devices. I can only see the following possibilities.

Dummy,B,B,A,B,Dummy

or

Dummy,B,A,B,B,Dummy

But I still suspect there would be linear gradients with the above two arrangements.

Please give me your suggestions to tackle this.
 

Use an extra B device which is not connected:
Dummy,B,B,A,B,B,Dummy
 

Or make it 2:6

DBBABBABBD or DBBBAABBBD or DABBBBBBAD

If they're wide enough that 2 fingers per leg makes
sense
 
dick_freebird said:
Or make it 2:6

DBBABBABBD or DBBBAABBBD or DABBBBBBAD

If they're wide enough that 2 fingers per leg makes
sense
Click to expand...

Which of the above two arrangements are preferred and why?
 

That, I couldn't tell you. All are center-symmetric. I
kind of like the first one as the reference devices
are most evenly distributed in the rack. But science,
I have none.
 
D,B,B,A,B,D
D,B,A,B,B,D

So many options...
 

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