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Designing a circuit with Schottky diode and a resistor in series

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ysrkreddy

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Hi all

Design a circuit by usuing a schottky diode and one single resistor, both should be in seris . And the availiable voltages are +5v,+3.3v,-5v,-3.3v.


regards
rama krishna
 

Re: design a circuit

what is the purpose of the circuit.... i mean what output do u expect from this circuit....
 

Re: design a circuit

ysrkreddy said:
Hi all

Design a circuit by usuing a schottky diode and one single resistor, both should be in seris . And the availiable voltages are +5v,+3.3v,-5v,-3.3v.


regards
rama krishna

What's the use of the circuit? rectifier?
 

Re: design a circuit

hi

the o/p from the design is 0.3v.

regards
rama krishna
 

Re: design a circuit

Hi,

If the output voltage should be 0.3V then you can use the available +3.3V supply.

Connect one leg of the series resistor to +3.3V output, its other leg goes to the anode of the Schottky diode and the cathode goes to the negative point of your +3.3V supply, ok? Simply you use the Schottky diode as a Zener diode.
Small and medium power Schottky diodes have a forward voltage drop of 0.15-0.4V, depending on how much forward current you pass through.
For instance, see the Characteristics Curves of this Schottky diode here:
http://www.semicon.toshiba.co.jp/eng/product/diode/selection/topics/1176538_2381.html

and you see 0.3V forward voltage drop around 35mA forward current, ok?

Now you can calculate the resistor value like you calculate for a normal Zener case, considering your output current need around the 0.3V output and this output is from the diode two legs of course.

Did you think this solution with the Schottky diode?

unkarc
 

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