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Question about modeling jitter as random variation of edges

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svensl

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JITTER QUESTION

I was modeling jitter as a random variation of the clock edges. So I randomly delay or advance a jitter free clock to obtain my non-ideal clock.
Now, since I have no experience with real life clocks I was wondering about the following:

Can it happen that one edge of a clock can be delayed by a certain amount, and the next consecutive edge advanced by a certain about such that they will overlap and the jittered clock will miss an edge?
Are there high frequency clocks that have missing edges due to jitter??

Thanks
 

Re: JITTER QUESTION

No.
what you are talking is about jitter equal to clock period. Then we are not talking about clocks.

BRM
 

Re: JITTER QUESTION

brmadhukar said:
No.
what you are talking is about jitter equal to clock period. Then we are not talking about clocks.

BRM
Click to expand...

Thanks for the response.
For a clock period T a jitter variation of T/4 would be sufficient, as T/4 delayed, plus T/4 advanced will already give an overlap.
 

Re: JITTER QUESTION

i think it is pretty much possible because if the astable multivibrator which provides us the clock signal gets affected by some disturbance i.e.noise, glitch etc then it is a possibility that it may stay in one state more than it is supposed to be.... but i think it is pretty rare......
 

Re: JITTER QUESTION

You are right, but what application are you looking at where you can tolerate such jitters. Even the worst quality crystal available in the market does not give you such a preformance :|
 

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