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About LVDS Driver Input

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litianmao

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I want to konw,when the Vdd is 1.8V ,Is the LVDS driver's Input signal Vin+ Vin- like
Vin+ 0 DC 0 Pulse 0 1.8V 0.05n 0.05n 0.05n 9.45n 20n
Vin- 0 DC 0 Pulse 1.8V 0V 0.05n 0.05n 0.05n 9.45n 20n ?
and we aim the Output signal from 1.0V to 1.4V ?

thanks !
 

LVDS, that's means low power differential signals,
the v+ and v- have the invert pase, and the swing magnitude can not reah rail-to-rail, so the peak value is less than power vdd.

Added after 3 minutes:

low swing magnitude can translate high speed signal,
the work well case can large than 500Meg. you can refer the IEEE LVDS & RSDS standard.

Added after 2 minutes:

LVDS is current driven data interface, the transmitter current can reach 1mA series a 100 ohm resistor.
 

I 'm doing a simulate about driver , the Vin+ Vin- is not rail to rail ?
then ,what signal are they ? what's the magnitude of the input signal .
thanks .
 

read and understand the lvds spec b4 you start to design or simulate anything. i haven't touch it for few years, but i still remember the vcm is 1.2V and +/- 200mV in differential.
 

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