masadi
Member level 4
im rather confused about adding two signals which have same freq or different.
No 1.
i have 2 signals V1 = A sin ωt volt and V2 = A sin 2ωt volt
the power of V1 = A²/2 and power V2= A²/2 , note that R normalized to 1
are those right ?
if i add V1 to V2, these two signals become V3=V1+V2 = A (sin ωt + sin 2ωt) volt
can i say that the power of V3 is sum of each signal power ?
Power V3 = power V1 + power V2 = A² ?????
No 2
i have two signals V1 = V2 = A sin ωt volt
the power of each signal PV1 = PV2 = A²/2.
V3 = V1 + V2 = 2A sin ωt volt , is it right??
Power of V3 = (2A)² / 2 = 4A²/2 = 2A²
I think it's absurd because i add two signals which each signal has power A²/2 and how come the result signal has power 2A²?? in my mind, it doest satisfy the law of energy conservation, because from where the difference power A² comes.
A²/2 + A²/2 should be A² not 2A².
it seems trivia problem but it's really confusing for me.
can anyone explain about that or tell me from where i went wrong in understanding it?
Thanks 4 ur helps
regard
masadi
No 1.
i have 2 signals V1 = A sin ωt volt and V2 = A sin 2ωt volt
the power of V1 = A²/2 and power V2= A²/2 , note that R normalized to 1
are those right ?
if i add V1 to V2, these two signals become V3=V1+V2 = A (sin ωt + sin 2ωt) volt
can i say that the power of V3 is sum of each signal power ?
Power V3 = power V1 + power V2 = A² ?????
No 2
i have two signals V1 = V2 = A sin ωt volt
the power of each signal PV1 = PV2 = A²/2.
V3 = V1 + V2 = 2A sin ωt volt , is it right??
Power of V3 = (2A)² / 2 = 4A²/2 = 2A²
I think it's absurd because i add two signals which each signal has power A²/2 and how come the result signal has power 2A²?? in my mind, it doest satisfy the law of energy conservation, because from where the difference power A² comes.
A²/2 + A²/2 should be A² not 2A².
it seems trivia problem but it's really confusing for me.
can anyone explain about that or tell me from where i went wrong in understanding it?
Thanks 4 ur helps
regard
masadi