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[SOLVED] Help me please. Can't compile hitech picc.

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Notty07

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Hi

I have some ploblem I can't compile with hitech picc.
It tell me not enough memory in bank0.
Because I use memory over 96byte.
How I can do it for use memory in another bank.

(I use picc8.01pl3 and mplab6.10)

Thank you.
 

Go to hts0ft suppport forum

**broken link removed**

And place you problem there .
 

hi fullmoon,
i don't know what is the type of pic you use but you probably have to place a bank# modifier in front of var, i.e.

bank3 unsigned char myarray[80]; // this array will be placed in bank3 of pic /i.e. 16f877/

see also and hi-tech picc manual!
Best regards!
 

Hi Stroma

I use pic16f877 .
I declare float data[100];
After build it show this message

Executing: C:\HT-PIC\bin\picc.exe -Q -MPLAB -C -16F877 tt.c -Ott.obj -Ett.cce -G
Executing: C:\HT-PIC\bin\picc.exe -Q -MPLAB -16F877 E:\test\tt.obj -Ett.lde -Ott.hex
Error[000] : Can't find 0x12C words for psect rbss_0 in segment BANK0
BUILD FAILED

How I can do.
 

Sorry, but you can't declare an array of 100 Bytes. Take a look at the datasheet (memory organization): in bank 0 there are only 96 Bytes for usage, in bank 1, 2 or 3 only 80 Bytes. You have to split your array in different banks. For float-variables there are 3 Bytes per value needed, so for your problem there are 300 Bytes needed. Split them in 4 banks (4 * 75 Bytes).


Mik
 

Hi fullmoon,

I cannot be sure, it'll be proper for your problem.
According my earler experience with PIC12xxx and PIC16xxx.

1st possible method is :
If you want a kind of look-up table, you can declare your array on
ROM or FLASH area using the instruction of const or flash.

2nd possible method is :
If you can change your source somewhat, change your array from 1X100
to aXb e.g. 2X50, 4X25 etc.

I hope to you can solve your problem with above, if those can applied.

Good luck.
:roll:
 

Hi fullmoon,

Probably you can’t declare such BIG array of data in one ram bank. If you _really_ need float number array, try to split it in different banks or choose pic18Fxxx.

Best regards.
 

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