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Two pointers on the same adress.

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m_t_blind

m_t_blind

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I have two pointers, one int and one char type :

int *p1;
char *p2;

I do:

p2 = (char*)p1

to get p1 data in bytes.

If there are data in (8bit)adresses (p1)=0x10, (p1+1)=0x12,(p1+2)=0x14.

Can read this data in byte form later whith the p2 pointer ?
 

That usually works fine.

Remember that char and int can have different bit widths on different systems. That's important if you want to create portable code.
 

m_t_blind said:
I have two pointers, one int and one char type :

int *p1;
char *p2;

I do:

p2 = (char*)p1

to get p1 data in bytes.

If there are data in (8bit)adresses (p1)=0x10, (p1+1)=0x12,(p1+2)=0x14.

Can read this data in byte form later whith the p2 pointer ?
Click to expand...


p1 should point a valid memory location. If thats is the program works fine. Otherwise it will crash.
*p1 = 0x10, *(p+1)=0x12, *(p1+2)=0x14 is correct.

p1 = 0x10 changes the address pointed by p1 to 10 but not the data.

Cheers
 

Yes it will work fine but take care of the memory organization little endian or big endian.

regards,
Amr.
 

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