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    Bilinear switched capacitor resistor equivalent resistance

    I am trying to find the equivalent resistance of the following circuit in baker's book.

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    How do you get the factor of 4 in the denominator? I am trying to get the answer by using the principle of transfer of charge and conservation of charge like in the case below:
    https://en.wikipedia.org/wiki/Switch...citor_resistor


    we can assume that the voltage on the left side of cap is Vin and on the right Vout.

    during phi1 voltage across the cap is V1-V2 and during phi2 voltage across cap is V2-V1. So shouldn't delta q be 2C(V1-V2)?

    so shouldn't the answer be 1/2Cf ?

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    Re: Bilinear switched capacitor resistor equivalent resistance

    The capacitor is charging from -ΔV to +ΔV in phase 1 and back in phase 2, total q = 4CΔV.



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    Re: Bilinear switched capacitor resistor equivalent resistance

    Quote Originally Posted by FvM View Post
    The capacitor is charging from -ΔV to +ΔV in phase 1 and back in phase 2, total q = 4CΔV.
    This is not clear.

    Let say the voltage at left side is V1 and on the right V2.

    When s1 is closed the voltage across C is V1-V2. The charge of C is C(V1-V2). Now s1 is opened and s2 is closed. The voltage across C is V2-V1 and the charge on it is C(V2-V1). So the charge transferred out of the capacitor should be C (V1-V2) - C (V2-V1) is 2C(V1-V2). Why is this quantity 2C(V1-V2) multiplied by 2 again?



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    Re: Bilinear switched capacitor resistor equivalent resistance

    Charge is transferred to the output also when s1 is closed. What you describe happens 2 times per clock cycle.


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    Re: Bilinear switched capacitor resistor equivalent resistance

    So I had one more question, what would be the expression output equivalent resistance for the following switched capacitor circuit. Here V2 is connected to gnd during phi2.

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