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Yes.Should Rout3 > Rout2 ? at DC
Series connection of capacitances.and at higher frequencies, for example 50GHz
Yes.
Series connection of capacitances.
So |Zout3| > |Zout2|.
Zout3=Rout3*1/(j*omega*Cout3)/(Rout3+1/(j*Cout3)).I want to know about the real(Zout3).
Even a simple model of "real Zout" at 50 GHz has to consider at least all transistor capacitances.
real(Zout3) is not equal to Rout3.
Can you surely understand Rout2 ?
Yes, you can see it, if you calculate the impedance with sufficient complex model.The problem I have is that when I have just a cascode connection, the circuit is stable but when I connect 3 or 4 transistors in the stack it is not stable anymore. The reason I see is the real part of output impedance of the stack is negative.