+ Post New Thread
Results 1 to 2 of 2

11th September 2019, 05:36 #1
 Join Date
 Apr 2017
 Posts
 69
 Helped
 1 / 1
 Points
 830
 Level
 6
[Moved]Separation of Each bits in 8 bit long(data type) Binary number in mikro c Pro
Hello All,
I want to convert long integer to (long)Binary and then separate each bit from my (long data type)Binary number into 8 long variables.
Not able to get correct output by below code, First tried in C (with Online compiler).
Please help me!
Code C  [expand] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
#include <stdio.h> void main() { long num=95,remainder, base = 1, binary = 0; while (num > 0) { remainder = num % 2; binary = binary + remainder * base; num = num / 2; base = base * 10; } printf("Its binary equivalent is = %ld\n", binary); binary >> 7; binary & 1; printf("New Binary: = %ld\n", binary); }
Last edited by BradtheRad; 11th September 2019 at 06:04. Reason: Added code formatted window

Advertisement

11th September 2019, 06:31 #2
 Join Date
 Feb 2014
 Posts
 18
 Helped
 1 / 1
 Points
 1,117
 Level
 7
Re: Separation of Each bits in 8 bit long(data type) Binary number in mikro c Pro
the main difference between int and long int is range only, the number which is not crossed the range of int is same in long also, except while we convert from decimal to binary, we have to add
zero's at remaining positions.
ex: int 95 > 00000000 00000000 00000000 01011111 in binary
long 95 > 00000000 00000000 00000000 00000000 00000000 00000000 00000000 01011111 in binary
Code C  [expand] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
/////////////////////////////////////////////// in below code i contains the number of digits in binary representation. then you can add remaining higher bits with zero's like : in above code i = 7(no of bits in binary i.e., 1011111) binNum[64:7] <= 0; // function to convert decimal to binary void decToBinary(int n) { // array to store binary number long binaryNum[64]; // counter for binary array int i = 0; while (n > 0) { // storing remainder in binary array binaryNum[i] = n % 2; n = n / 2; i++; } // printing binary array in reverse order for (int j = i  1; j >= 0; j) cout << binaryNum[j]; }
Last edited by FvM; 11th September 2019 at 08:18. Reason: Added syntax tags
1 members found this post helpful.
+ Post New Thread
Please login