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    Half bridge SMPS xformer turns calculation

    dear i 'm not good in english.
    i have question that i have calculate the half bridge xformer
    primary turns ≈ 40, using formula N(prim) = (Vin(nomi) * 0.5 * 10^8)/(4*fs*Bmax*Ae).

    where Vin(nomi) = 311vdc
    fs = 50KHz
    Bmax = 1500 mT
    Ae = 1.3 cm-sq.
    Duty cycle = 0.98

    with N(sec) ≈ 14 turns for 22 volt output Vsec = 22volt
    & N(auxiliary) = 11 turns for 18volt.

    is this calculation correct ? can any one help me regarding this calculations?
    Last edited by codemaster11; 2nd September 2019 at 09:24.

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    Re: Half bridge SMPS xformer turns calculation

    Hi,

    For Bmax of 1500mT, what core material are you using?
    For duty cycle of 0.98, how did you arrive at that figure?
    Also why are you calculating with the nominal value?

    - - - Updated - - -

    Always bear in mind that parts are best selected at worst case conditions. For this topology, you would be using Vin_min.
    -------------
    --Akanimo.



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    Re: Half bridge SMPS xformer turns calculation

    How did you select the core size? You need to follow through a series of steps to help you do a good selection.

    You would have a lot of hits from a single internet search.
    -------------
    --Akanimo.



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    Re: Half bridge SMPS xformer turns calculation

    Quote Originally Posted by Akanimo View Post
    Hi,

    For Bmax of 1500mT, what core material are you using?
    For duty cycle of 0.98, how did you arrive at that figure?
    Also why are you calculating with the nominal value?

    - - - Updated - - -

    Always bear in mind that parts are best selected at worst case conditions. For this topology, you would be using Vin_min.
    i 'm using core EI33 with Ae = 1.3cm-sq from a readymade half bridge smps circuit. but i want to

    wind it myself with.

    i saw an example with duty cycle = 0.98. if it is not good what possible duty cycle i should use?

    i take vin(nomi) = 311vdc. where in formula we will take half of this value for half bridge topology.

    vin(nomi) = 311/2 vdc.

    if i take vin(min) = 100*√2 = 141vdc then vin(min) = 141/2 vdc. calculate N(prim) ≈ 18 turns.

    can this might be the right numbers of N(prim)?

    also for calculating i N(prim) i will take half of Vin(min)?



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    Re: Half bridge SMPS xformer turns calculation

    Quote Originally Posted by Akanimo View Post
    How did you select the core size? You need to follow through a series of steps to help you do a good selection.

    You would have a lot of hits from a single internet search.

    http://tahmidmc.blogspot.com/2013/02...lation_22.html

    for transformer i 'm referring above URL. is the calculation based on this is correct?

    they consider half of the full 311Vdc for Vin = Vnomi.

    also for calculating Nsec & Naux they use the Duty cycle.



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    SMPS transformer for Half bridge topology

    Click image for larger version. 

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    i enter the operating conditions according to my specification

    fs = 50000Hz

    Bmax = 1786mT.

    & powerEsim calculate N0 = 10T (AWG24 x 6)

    Nsec(N4 + N5 ) = (5 + 5) turns (AWG20 t/w x 3)

    could i use this transformer according to my specifications?



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    Re: Half bridge SMPS xformer turns calculation

    To design a half bridge transformer, first design a virtual buck converter with your vout. Decide what is your max duty cycle (say 0.7).
    So you then design a buck with whatever vin gives your vout with your chosen D.
    Then think about that “virtual” vin value.
    That virtual vin is what you must get out of your transformer when it has your minimum actual vin at its primary side.
    (but remember that with ˝ bridge your actual vin is half of the actual vin, so to speak…..because of the divider caps)
    So you then do the transformer equation vpri/vsec = Npri/Nsec
    ….thats pretty much it.
    If you are wondering about how many turns exactly to use, and what exact core etc, and you want an exact formula which spits out everything for you in one go then this is the wrong field for you……you have to do it iteratively and you converge to the solution.
    But this is good as it enables you to use your artistic side.
    You can use any core or wire you like as long as………………..
    Solution is not too big
    Wire loss not too high
    Core loss not too high
    Coupling not too poor.
    Skin effect is accounted for
    You can physically terminate the wire to the former pins.
    Etc etc etc….
    Here is my smps maths course to give you some of the equations for magnetics
    https://massey276.wixsite.com/maths

    and here is my electronics degree advisor
    https://massey276.wixsite.com/electronicsdegree



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    Re: Half bridge SMPS xformer turns calculation

    Your Bmax is about factor 10 too large. Please notice that quoted Tahmid's blog is calculating in antique unit Gauss rather than mT.



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    Re: Half bridge SMPS xformer turns calculation

    i wrote mistakenly 1500mT. it's 0.1500T or 1500 gauss.


    1 members found this post helpful.

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