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How can the Reactive part of Zopt absorbed into the drain line in a DA

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circuitking

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Hi, I was reading the paper "OPTIMUM DESIGN OF DISTRIBUTED POWER-FET AMPLIFIERS. APPLICATION TO A 2 - 18 GHz MMIC MODULE EXHIBITING IMPROVED POWER PERFORMANCES " and came across this
The output equivalent capacitances Copt, of the transistors have been absorbed into the drain line..

Let's say the output capacitance of a gain stage is Cout and for this gain stage optimum load is Yopt = Gopt+jCopt. It is possible to absorb Cout into artifical transmission line but how can the Copt be absorbed? Usually Copt and Cout values are different, If they are same it is not a problem.
 

pancho_hideboo said:
Consider Copt > Cout.
Click to expand...

Is Copt value really in my hands? I am thinking that I would get it from loadpull.

- - - Updated - - -

circuitking said:
Hi, I was reading the paper "OPTIMUM DESIGN OF DISTRIBUTED POWER-FET AMPLIFIERS. APPLICATION TO A 2 - 18 GHz MMIC MODULE EXHIBITING IMPROVED POWER PERFORMANCES " and came across this
The output equivalent capacitances Copt, of the transistors have been absorbed into the drain line..

Let's say the output capacitance of a gain stage is Cout and for this gain stage optimum load is Yopt = Gopt+jCopt. It is possible to absorb Cout into artifical transmission line but how can the Copt be absorbed? Usually Copt and Cout values are different, If they are same it is not a problem.
Click to expand...

I want the output capacitance of the gain stage be absorbed into the artificial transmission line and after that the gain stage should be able to see it's Zopt at the output, is it even possible?
 

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