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2nd July 2019, 08:22 #1
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2nd July 2019, 10:54 #2

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2nd July 2019, 11:11 #3
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Re: butterworth and chebyshev filter
(3.24) is due to complex conjugate pair of poles.

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2nd July 2019, 11:46 #4
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Re: butterworth and chebyshev filter
Consider coefficients of polynomials.
Calculate S11 from S21.
Then calculate Zin.
Then evaluate gparameters by continuation fraction expansion of Zin.
See https://www.edaboard.com/showthread....erosofS11(s)
All zeros of S11 are located at origin for Butterworth filter.
So you can get Both S11 and Zin as close form.Last edited by pancho_hideboo; 2nd July 2019 at 12:03.
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