# Series rlc and parallel rlc circuits

1. ## Series rlc and parallel rlc circuits

How can the voltage across a capacitor or inductor in a series RLC circuit be greater than the applied AC source voltage? Also for Parallel RLC, how can the current of anyone branch can be larger than the AC source current?

Please explain to me the mechanism as to how these phenomenon are possible. THANK YOU!  Reply With Quote

•

2. ## Re: Series rlc and parallel rlc circuits

The electrons move back and forth between the capacitor and the inductor.
Compare this movement with a mechanical pendulum. It can move much more than the movement you used to push it.
It is the same with the electrons.  Reply With Quote

•

3. ## Re: Series rlc and parallel rlc circuits

Taking the RLC series circuit as an example, all elements carry the same current, but voltages have different, even opposite phase according to the reactive nature of C and L. The behavior can be best visualized with phasor diagrams. https://en.wikipedia.org/wiki/Phasor

If you reduce R in the linked diagram and make XR and XC more equal, you'll see that the internal voltage can be a large multiple of the external voltage.   Reply With Quote

•

4. ## Re: Series rlc and parallel rlc circuits Originally Posted by FvM Taking the RLC series circuit as an example, all elements carry the same current, but voltages have different, even opposite phase according to the reactive nature of C and L. The behavior can be best visualized with phasor diagrams. https://en.wikipedia.org/wiki/Phasor

If you reduce R in the linked diagram and make XR and XC more equal, you'll see that the internal voltage can be a large multiple of the external voltage. How about in parallel RCL? How can a current in any one branch be greater than the source current?  Reply With Quote

5. ## Re: Series rlc and parallel rlc circuits

How about in parallel RCL? How can a current in any one branch be greater than the source current?
Sure, basically a similar phasor diagram as for series RLC, just flip voltage and current.  Reply With Quote

--[[ ]]--