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Measure impedance of rectifier using harmonic balance in ADS software

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edalpy

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I am trying to use harmonic balance to find the impedance of the voltage double rectifier. After finding the impedance, I will use the impedance matching tool to find out the L matching.

As the pictures show, the frequency is 915MHz and power is 0dbm. I had got some result after simulation. Z0=50ohm, impedance of V1=Z0(4.108-j0.479), impedance of Vout=Z0(1-j7.163E-10).

But I am confused which point of impedance should be used to do impedance matching, V1 or Vout? 捕获.JPGw321.JPG212.JPG
 

What do you mean by V1 and Vout ?

They are complex voltages not impedances.

Edited by Dora: arrogant phrasing removed.
 

Large Signal/Nonlinear Impedances are not simulated as you did..
Use I.Probe component and Define Impedance being as :

Z=V<complex quantity>@freq/I.Probe.i <complex quantity>@freq=<complex quantity>@freq
 

Thanks. I know the definition of the impedance. V1 and Vout are just name of the two points instead of voltage. They are not voltage. Maybe I should say "Z0=50ohm, impedance of point V1 is Z0(4.108-j0.479), impedance of point Vout is Z0(1-j7.163E-10).

- - - Updated - - -

LOL. Why it shows the impedance on the smith chart of point V1 and Vout directly? It's not the impedance of point V1 and Vout?
 

edalpy said:
Thanks. I know the definition of the impedance. V1 and Vout are just name of the two points instead of voltage. They are not voltage. Maybe I should say "Z0=50ohm, impedance of point V1 is Z0(4.108-j0.479), impedance of point Vout is Z0(1-j7.163E-10).
- - - Updated - - -
LOL. Why it shows the impedance on the smith chart of point V1 and Vout directly? It's not the impedance of point V1 and Vout?
Click to expand...

I don't think that you know what the Impedance is..
The value which you saw on the Smith Chart is a Complex Quantity of the Voltages, not Impedances..Smith Chart does not show Impedances only, it's an Abaqus and it show any Complex Normalized Quantity whatever is..
You have a long road to run..
 

Sorry, I'm a beginner. But it does show "impedance", as this picture show . It's not impedance?21.png
 

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Locus is a reflection coefficient not impedance in Smith Chart.

Edited by Dora: arrogant phrasing removed.
 

You mean the word "impedance " in the picture refers to locus? It's not really impedance? My understanding is the the load impedance should equal to the complex conjugate of the source impedance in order to get maximum power transfer. If Zsource=50+20j, we should using matching network(capacitors and inductors) make Zload=50-20j.
 

In dc circuit impedance=resistance while in AC circuit impedacne=resistance+reactance
 

Maybe I can ignore the rectifier and just consider the load?
 

Smith Chart is a plot of reflection coefficient not impedance.

Zin=Vin[1]/Iin[1] ; Input Impedance for fundamental
Sin=(Zin-Z0)/(Zin+Z0), Z0=50

Plot Sin not Iin.

Edited by Dora: arrogant phrasing removed.
 
Last edited:

Ok. I can understand the reflection coefficient. The smith chart does not show impedance. The point is that I thought that the software calculate the impedance and show it automaticlly. As the picture shows, it's "impedance=Z0*(4.108-J0.479)". Can you see the picture?:grin:
 

edalpy said:
As the picture shows, it's "impedance=Z0*(4.108-J0.479)". Can you see the picture?:grin:
Click to expand...
You are completely misunderstanding.

Your V1 and Vout are not impedance.
If you plot Reflection Coefficient, marker of Smith Chart show impedance.


Edited by Dora: arrogant phrasing removed.
 
Last edited:

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