ivan_mateo
Member level 1
Hi everyone;
I am planning to design 100kHZ pwm circuit for half bridge converter but there is some confusion for me in this circuit that I showed below. As I understand from this circuit, Vref=5.1v and two 4k99 resitor divide it to 2.55V and it connect to noninverting input. When the inverting input(pin1) is higher than noninverting input(pin2), duty cycle will be decreased means that ic will not give pwm out.
But is it right? I do not understand function of eout(pin3). Can anybody explain it?
I am planning to design 100kHZ pwm circuit for half bridge converter but there is some confusion for me in this circuit that I showed below. As I understand from this circuit, Vref=5.1v and two 4k99 resitor divide it to 2.55V and it connect to noninverting input. When the inverting input(pin1) is higher than noninverting input(pin2), duty cycle will be decreased means that ic will not give pwm out.
But is it right? I do not understand function of eout(pin3). Can anybody explain it?