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Charateristics of {A,B ; C,D} Matrix for lossless circuit

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pancho_hideboo

pancho_hideboo

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As well known, Scattering Matrix is a unitary matrix for lossless circuit.

Is there any simple relation in [F]={A,B ; C,D} Matrix for lossless circuit ?
Reciprocity is reflected to determinant(F)=1.

Here {A,B ; C,D} Matrix is called as "Fundamental Matrix", "Ketten Matrix", "Cascade Matrix" or "Chain Matrix".
 

Hmm, I like these sort of puzzles. I'll give it a shot.

If A and D are real valued and B and C are imaginary valued, then it should be lossless.

I base this on the fact that impedance parameters of a lossless network are all imaginary, and the known conversions from Z parameters to ABCD parameters.
 

Thanks for response.

mtwieg said:
If A and D are real valued
and B and C are imaginary valued,
then it should be lossless.
Click to expand...
[F] Matrix of Lossless Transmission Line is a simple example.

A=D=cos(beta*L)
B=j*R0*sin(beta*L)
C=j*(1/R0*)sin(beta*L)
 

It is assumed that ABCD-parameters are defined by the following equations:
V1 = A*V2 - B*I2,
I1 = C*V2 - D*I2.

No-loss condition:
0 = real(conj(V1)*I1 + conj(V2)*I2)

= real(conj(A*V2 - B*I2)*(C*V2 - D*I2) + conj(V2)*I2)

= real(conj(A)*C*conj(V2)*V2)
+ real(conj(B)*D*conj(I2)*I2)
+ real((1 - conj(A)*D)*conj(V2)*I2)
- real(conj(B)*C*conj(I2)*V2)

= real(conj(A)*C*conj(V2)*V2)
+ real(conj(B)*D*conj(I2)*I2)
+ real((1 - conj(A)*D - B*conj(C))*conj(V2)*I2).

Consequently,
real(conj(A)*C) = 0,
real(conj(B)*D) = 0,
conj(A)*D + B*conj(C) = 1.
 

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