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CDS circuit for CCD readout

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filip.amator

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Hi!

I am doing a noise analysis of CDS circuit used for pixels readout from CCD sensor. We want to measure voltage difference between reference level and data level. The S1 and S3 switch are closed during reference level phase and later opened during the 'data level' phase. The C7 cap during reference phase is charged (right side is grounded) and later will be discharged from reference level to actual pixel level. My question is: what is the role of U3 and C8?
It looks like an integrator but it is a very uncommon configuration: voltage at C7 is a ground/ref at non-inverting input of U3 and the input bias current is integrated at C8. When S3 is closed it is an ordinary voltage follower.

ccd_fig1.gif



cds.png
 

You probably need to know the relation of the second
figure's switch control phases, to the first. The second
figure is an integrator with reset. +IN goes to zero and
feedback shorts, and you get Vout=0.

How the output buffer behaves is obscured by the lack
of "species indicators" (I would tend to assume the two
FETs are PMOS but have seen enough ROIC designs to
know not to believe anything particularly, offhand). How
the sampling (data level) happens between top and
bottom figure seems to be a missing piece. Without
the actual sampling (twice) the integrator is going to
be integrating a bunch of irrelevant cr@p. I am suspicious
about the nature of cds_in signal relative to the "CCD
output voltage" signal. Are they the same, as "drawn"?
 

Hi,
If C8 is shorted every cicle it's not an integrator. An integrator needs to hold the prevoius output voltage.It could be a switched capacitor amplifier.
 

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