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Statistic and probability problem with a given sample

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jackobian

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Statistic and probability

In monitoring the results of students at the end of the semester of the statistics, it was found that the success rate of male students reached 60% and the success rate of female students was 70%. A random sample of 81 results was withdrawn from the results of the male students, and a random sample of 100 results was retrieved from the results of the female students

Calculate the probability that the percentage of successful students in the first sample is better than the students in the second sample

any idea please??? i am not expert in math very well
 

Re: Statistic and probability

I think we can reason this way:

60% success of 81 samples means 49 sucessful and 32 fail
in order to reach the same number of samples we have to add 100-81=19 students to the first record.

Even if all of them will be succesfull we will reach 49+19=68, that is 68 % succes rate, that means we have 0 % probability the first sample will be better than the second one.
 

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