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[SOLVED] [moved] Regarding password changing function in C

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achar.deepak

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Dear All,

I have written a code for password managing function in C. I need to change the password from default password. I have attached my code. The password is not updating. Please help. Thanks in advance.

Code: 
#include <stdio.h>
#include <string.h>
#include <conio.h>
#include <stdlib.h>

char loginpassword[10];
int Current_mode = 2;
int num;
int value_store;

void change_password(void);
char *Password_Ascii_function(void);

int main (void)

{

	printf("Password Manager:\n");

	char defaultascii[5] = "1234", count;
	
	char *returnacii;

	strcpy(loginpassword ,"Enter Password");
	
	printf(loginpassword);

	printf("\n");

	while(1)
	{

			returnacii = Password_Ascii_function();	
		
	   		if(strcmp(returnacii, defaultascii)==0)
       		{	
       			returnacii[0] = '0';
       			returnacii[1] = '0';
       			returnacii[2] = '0';
				returnacii[3] = '0';
       			       			
       			strcpy(loginpassword, "Enter New Password");

				printf("\n");
			    
				printf(loginpassword);

				printf("\n");
                
				returnacii = Password_Ascii_function();
                
                defaultascii[0] = returnacii[0];
                defaultascii[1] = returnacii[1];
				defaultascii[2] = returnacii[2];
                defaultascii[3] = returnacii[3];

				printf("\n");
                
                printf("Password changed, Login again:");

				printf("\n");

                main();                    
            }
            else
	 		{
	  			strcpy(loginpassword,"Wrong Password");
					  			
				count=count+1;
        	
				if(count>=4)
        		{
	           		strcpy(loginpassword,"Default Password");
            	    
					printf(loginpassword);
										
					defaultascii[0] = '1';
            		defaultascii[1] = '2';
            		defaultascii[2] = '3';
            		defaultascii[3] = '4';
            		defaultascii[4] = '\0';            			
            		
					strcpy(loginpassword, defaultascii);
                }
	  		 }

		printf(loginpassword);
				
	}

	getch();
	return 0;
}

char *Password_Ascii_function(void)
{
	
	char pasword[10],usrname[10], ch;
    int i;
 
      for(i=0;i<4;i++)
        {
			ch = getch();
			pasword[i] = ch;
			ch = '*' ;
			printf("%c",ch);
		}
 
       pasword[i] = '\0';

       return pasword;

}

Regards
Deepak A B C
 

You are not updating the new password at the flash memory.
Your code will allways retrieve the default password.
 

Hi,

I am not using any flash memory here. Please help.

Thanks
Deepak
 

char *Password_Ascii_function(void);
Click to expand...
Try chaging that to: void Password_Ascii_function ( char * ) where you send "returnacii" directly as an argument on the function and you modify it.

If I remember right, the below ones in the function will be destroyed after the function is over. So the "return password" is basically "trash".
char pasword[10],usrname[10], ch;
Click to expand...
 

Hi,

Here I am getting error as Password_Ascii_function: Function does not take 0 arguments. Please help.

Thanks
Deepak
 

Considering that the password has invariably 4 digits, why do are you adding extra complexity to the code by using pointer to function, whereas this could be achieved in a simplest fashion just by using global variables instead ?
 

why there is an extra call to main() in your code ?
 

Anyway, the code as a whole need to be deeply reviewed.
For example, the following function:
Code: 
strcpy(loginpassword ,"Enter Password");
Is going to load an array of 14 characters at a variable loginpassword previously declared as having 10 bytes lenght.
 

Talking about errors, I hope the OP was joking here:
Code: 
printf(loginpassword);
And many others... In a nutshell, that code is far from working.
 

Hi andre_teprom

Thanks. I got the solution.

Thanks
 

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