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solve algebraic equation

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amirhossein20n

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hello friends

i need to solve these equations urgently and extract x and y in function of w , separately

i heed your help

ep.mue..JPG
 

You can use matlab or mathematica software tool which are used to solve such equations.
Scilab is also free tool in case you do not have matlab license.
 

Yeah, you can't have entire functions as unknowns.


In general for solving algebraic functions symbolically Microsoft Mathematics is free and quite powerful.
 

hi pancho_hideboo

why ??

you mean we cant separate X , y ??

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i do with matlab and maple but exactly im not skillful ,
can you help me?
 

If A and B are constant I am not getting the reason that why there is no solution in terms of omega?
We have two equations and two variables.
Please tell me why there is no solution as I am getting all curious now
 

not surely , in reality A, B are constant

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hi nomigoraya
im sympathetic to your Point of view , but i baffled
 

I will follow this thread to understand what I misunderstood.
Waiting for the reason if there is no solution.
 

The product \[X(\omega)Y(\omega)\] has a unique value for each \[\omega\]

Then, never be simultaneously \[A+\frac{1}{\omega^2}\] and \[B+\frac{4}{\omega^2}\], unless A or B are functions of \[\omega\] and \[A(\omega)+\frac{1}{\omega^2} = B(\omega)+\frac{4}{\omega^2}\]

However, you would find only the product, not the factors.
 

hi _Eduardo_

yes you re right ,w has influence on A and B , but important thing must be remarked is that A,B haven't a simple relation with w .but totally yes we could interpret A(w),B(w)
 

but important thing must be remarked is that A,B haven't a simple relation with w.
but totally yes we could interpret A(w),B(w)
This contradicts your following append.
not surely , in reality A, B are constant

You also should surely reconsider a start of this thread by yourself.

A-B has to be equal to 3/(w^2).

So X*Y=B+4/(w^2)=A+1/(w^2).

Simply your two equatios have no meaning.
There is only one equation for X*Y.
 
Last edited:
A-B has to be equal to 3/(w^2).

So X*Y=B+4/(w^2)=A+1/(w^2).

Simply your two equatios have no meaning.
There is only one equation for X*Y.
Thanks a lot for such detailed answer now I can understand what was the tricky part of question
 

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