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Solving an nonlinear equation

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c_mitra said:
The next step you missed: c must be zero.
Click to expand...
c_mitra said:
In the present case,
the right hand side does not have a solution in x except the trivial solution of c=0
Click to expand...
Very nonsense.

Do you think c=0 has any meaning ?

c=0 means that we completely ignore RHS.

Your appends simply result in raising confusion for amirhossein20.

Real number solution for x can never exist for this nonlinear equation as far as a, b, and c are all real number.
 
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amirhossein20n said:
yes a,b,c are real

and x is complex in form of Q+jk , for exapmle.
Click to expand...

sorry for the confusion. I presumed (wrongly) that x was real. If it is, instead, complex the solution can exists, but to find it in a closed form is quite difficult. The procedure is always the same: find real and imaginary parts of both lhs and rhs and equate in a system of two equations:

real(lhs)=real(rhs)
imag(lhs)=imag(rhs)

where Q and K will be the two unknowns

We know that exp(a+jb)=exp(a)*cos(b)+j*exp(a)sin(b) then:

exp(-2x)=exp(-2Q)*cos(-2K)+j*exp(-2Q)*sin(-2K)
exp(2x)=exp(2Q)*cos(2K)+j*exp(2Q)*sin(2K)

We know also that cos(z)=cos(-z) and sin(z)=-sin(-z) thus:

exp(-2x)=exp(-2Q)*cos(2K)-j*exp(-2Q)*sin(2K)
exp(2x)=exp(2Q)*cos(2K)+j*exp(2Q)*sin(2K)

but now is very difficut to proceed to obtain a closed form solution
 

i wanna clear some thing :

for solvig this equa, we can do numerically and analitically , ok , when you offer that transpose to the other side and plot ,so it make numeric solution such as interpolation , newton ... .
but for analitical solve , because i neeed x=x(c) function i think we need to inverse the first function i write in first post
that change c=c(x) to x=x(c) .
in other words, we dont need solve this exactly . just by inversing the first function we reach to the x=x(c) that is suficient for us .
 

can you explain what does the codes do,please ?

- - - Updated - - -

i mean inversing i need

for example this :
4.JPG

simply
 

ok , you wanna say we cant write this structure for my case ??
can this function solve my equa?
 

Can you understand my appends ?

Analytical solution, that is, closed form solution can not exist for your nonlinear equation.

amirhossein20n said:
you wanna say we cant write this structure for my case ??
Click to expand...
I can not understand what you want to mean at all.
What do you mean by "this structure" ?
Describe correctly.

amirhossein20n said:
can this function solve my equa?
Click to expand...
What do you mean by "equa" ?
Don't use unfamiliar abbreviation.

Analytical solution, that is, closed form solution can not exist for your nonlinear equation.

Can you understand a meaning of analytical solution or symbolic solution ?

However we can solve your nonlinear equation numerically while varying c value.
 

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what's this program, you used ??

(i didnt seen mathematical program with dark black background, so far)
 

c_mitra said:
You appear to forget that zero is also a real number.
Click to expand...
No.
c=0 results in a meaningless solution.
We have to consider a!=0, b!=0 and c!=0 for solutions which have meaning.

All your and albbg's appends don't hit point at all but simply cause confusion for amirhossein20.
 
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