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ORING in if condition

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Is this a correct way of using if with ORING

Code: 
if((alarm_flag_c1_f1)==((0b01000000)||(0b01100000)||(0b01100010)||(0b00100010) ||(0b01000010)||(0b00100000)||(0b00000010)))
 

It is done like this.

Code C - [expand]
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if((alarm_flag_c1_f1 == 0b01000000) || (alarm_flag_c1_f1 == 0b01100000)  || (alarm_flag_c1_f1 == 0b01100010) || (alarm_flag_c1_f1 == 0b00100010) || (alarm_flag_c1_f1 == 0b01000010) || (alarm_flag_c1_f1 == 0b00100000) || (alarm_flag_c1_f1 == 0b00000010)) {
 
}
 
If the 3 bits tested is the only ones used in 'alarm_flag_c1_f1' this should work. If one or more of the rest of the bits are used or not '0', you will have a problem and may not get a true result. To get that you need to AND the variable befor you do the test.

Analyzing your test patterns, you could also just AND with '0b01100010', and skip all the ORing. You are using 3 bits with 7 variants, that leaves only the all '000' variant. As long as atleast one of the 3 bits is '1' your test is true.
 
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