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It occurred to me that adding the two quadrature outputs of a DDS like the AD9854 might result in an output without the image frequency component, thereby making the filtering much less critical.
In other words, with F0=100MHz, and an output set to F1, say 10 MHz, the image at F0-F1 would be cancelled out if I added the real and quadrature outputs, ignoring phase errors, etc.
Is this true?
In other words, with F0=100MHz, and an output set to F1, say 10 MHz, the image at F0-F1 would be cancelled out if I added the real and quadrature outputs, ignoring phase errors, etc.
Is this true?