[SOLVED] Equations for Peak-to-Peak Output Voltages for Differentiator and Integrator

pavan garate said:

Hi...

I want to design the differentiator and integrator using OPAmp (IC 741) and verify it for the sine wave input and square wave input. I know the nature of the output waveforms.

Can anyone tell me the equations for peak-to-peak output voltages for differentiator and integrator when sine wave and square wave are applied as the inputs..???

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Audioguru said:

The sine wave output signal level will be 0.707 times the unmodified input level when the differentiator or integrator are at the cutoff frequency.
The square wave will have a unique differerentiated or integrated appearance but I do not know the formula for the output level.

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Audioguru said:

The sine wave output signal level will be 0.707 times the unmodified input level when the differentiator or integrator are at the cutoff frequency.
The square wave will have a unique differerentiated or integrated appearance but I do not know the formula for the output level.

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pavan garate said:

I know that-
1) For sine wave input- Both the integrator and differentiator will give the cosine wave at output.
2) For square wave input- Integrator will give the triangular wave and differentiator will give the spikes at the output.

I want to know the theoretical formulae for calculating the peak-to-peak voltage for all these four outputs. I have designed and simulated these circuits using OrCAD. I want to check whether I'm getting the correct outputs or not. Merely getting the correct shapes of output waveforms does not mean that I'm getting the correct results. There must be some formulae to find the peak-to-peak voltage for such outputs.

Thanks...

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