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Network + Subnetting question.

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xizor

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Hello all,
I am currently study for network + and i am reading Mike Myers forth edition Comptia Networking +.
I am trying to figure out when subnetting IP address do you end up with a range of subnets along with a range of IP address?
For example I subnet a class c ip/subnet into two for /25
Do i now have two subnet mask?
192.168.1.0 with subnet mask of 255.255.255.0 subnet #1
192.168.1.128 with subnet mask of 255.255.255.128 subnet #2

I am confused on this point.

Thanks in Advanced!
 

hi.i think you do not have 2 subnet masks.you have two networks
192.168.1.0 - 192.168.1.127
192.168.1.128 - 192.168.1.225
both ip ranges have subnet mask : /25
each number ,divided by commas , is correspond to a binary number.
for 192.168.1.0 to 192.168.1.127 the binary is 11000000.10101000.00000001.0xxxxxxxx
so all ip addresses in this network share first 25 bits.
for 192.168.1.128 to 192.168.1.255 the binary is 11000000.10101000.00000001.1xxxxxxxx
so when you make subnet from a /24 mask, instead of having 255 devices which share 24 bits,you have 2 , 128 devices which share 25 bits in their ip address.
tnx
 

networks 192.168.1.0 and 192.168.1.128 have similar subnet /24 (255.255.255.0). this is the host or the ip address you can use in your devices 192.168.1.1~126 (255.255.255.0) /24 in your first subnet. while in second subnet 192.168.1.129~24 (255.255.255.0) /24. so basically when you subnet a network, that network have similar subnet mask

subnet mask for networks

/24 - 255.255.255.0
/25 - 255.255.255.128
/26 - 255.255.255.192
/27 - 255.255.255.224
etc...
 

brian25 said:
networks 192.168.1.0 and 192.168.1.128 have similar subnet /24 (255.255.255.0). this is the host or the ip address you can use in your devices 192.168.1.1~126 (255.255.255.0) /24 in your first subnet. while in second subnet 192.168.1.129~24 (255.255.255.0) /24. so basically when you subnet a network, that network have similar subnet mask
etc...
Click to expand...

I suppose mask of /24 was a typo. It should be /25 for 2 networks.
 

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